At an osmotic pressure of 24 atm, what is the approximate concentration of NaCl in sea water?

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Multiple Choice

At an osmotic pressure of 24 atm, what is the approximate concentration of NaCl in sea water?

Explanation:
To determine the concentration of NaCl in sea water at an osmotic pressure of 24 atm, we can use the concept of osmotic pressure, which is given by the formula: \[ \Pi = i \cdot C \cdot R \cdot T \] where: - \( \Pi \) is the osmotic pressure, - \( i \) is the van 't Hoff factor (which is the number of particles the solute dissociates into), - \( C \) is the molar concentration of the solute, - \( R \) is the ideal gas constant, and - \( T \) is the absolute temperature in Kelvin. For NaCl, it dissociates into two ions: Na\(^+\) and Cl\(^-\). Therefore, the van 't Hoff factor \( i \) for NaCl is approximately 2. Assuming a standard temperature (about 298 K), we can calculate the concentration \( C \) needed to reach an osmotic pressure of 24 atm. Rearranging the formula gives: \[ C = \frac{\Pi}{i \cdot R \cdot T} \] Substituting the values into the equation: - \(

To determine the concentration of NaCl in sea water at an osmotic pressure of 24 atm, we can use the concept of osmotic pressure, which is given by the formula:

[ \Pi = i \cdot C \cdot R \cdot T ]

where:

  • ( \Pi ) is the osmotic pressure,

  • ( i ) is the van 't Hoff factor (which is the number of particles the solute dissociates into),

  • ( C ) is the molar concentration of the solute,

  • ( R ) is the ideal gas constant, and

  • ( T ) is the absolute temperature in Kelvin.

For NaCl, it dissociates into two ions: Na(^+) and Cl(^-). Therefore, the van 't Hoff factor ( i ) for NaCl is approximately 2.

Assuming a standard temperature (about 298 K), we can calculate the concentration ( C ) needed to reach an osmotic pressure of 24 atm. Rearranging the formula gives:

[ C = \frac{\Pi}{i \cdot R \cdot T} ]

Substituting the values into the equation:

  • (
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